A: Novoaleksandrovskoye city of country Russian Federation lies on the geographical coordinates of 56° 13' 0" N, 40° 15' 0" E.
Latitude and Longitude of the Novoaleksandrovskoye city of Russian Federation in other units:
| Unit | Latitude | Longitude |
| Latitude and Longitude to decimals | 60.0 | 100.0 |
| Latitude and Longitude to degrees minutes seconds | 56° 13' 0" N | 40° 15' 0" E |
| Latitude/Longitude to UTM Reference |
| UTM Northing:6230901.183380645 Easting:577520.6390703426 Zone:37V |
| View Latitude of Russian Federation. |
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