A: Novoaleksandrovskoye city of country Russian Federation lies on the geographical coordinates of 44° 55' 22" N, 44° 15' 50" E.
Latitude and Longitude of the Novoaleksandrovskoye city of Russian Federation in other units:
| Unit | Latitude | Longitude |
| Latitude and Longitude to decimals | 60.0 | 100.0 |
| Latitude and Longitude to degrees minutes seconds | 44° 55' 22" N | 44° 15' 50" E |
| Latitude/Longitude to UTM Reference |
| UTM Northing:4974637.838722853 Easting:441906.25647594966 Zone:38T |
| View Latitude of Russian Federation. |
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