A: Aleksandropol city of country Russian Federation lies on the geographical coordinates of 53° 4' 0" N, 54° 21' 0" E.
Latitude and Longitude of the Aleksandropol city of Russian Federation in other units:
| Unit | Latitude | Longitude |
| Latitude and Longitude to decimals | 60.0 | 100.0 |
| Latitude and Longitude to degrees minutes seconds | 53° 4' 0" N | 54° 21' 0" E |
| Latitude/Longitude to UTM Reference |
| UTM Northing:5882973.45555042 Easting:322449.16435587546 Zone:40U |
| View Latitude of Russian Federation. |
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